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40x^2-141.5+3.33=0
We add all the numbers together, and all the variables
40x^2-138.17=0
a = 40; b = 0; c = -138.17;
Δ = b2-4ac
Δ = 02-4·40·(-138.17)
Δ = 22107.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{22107.2}}{2*40}=\frac{0-\sqrt{22107.2}}{80} =-\frac{\sqrt{}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{22107.2}}{2*40}=\frac{0+\sqrt{22107.2}}{80} =\frac{\sqrt{}}{80} $
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